Pressure coefficient Cp is defined as Cp=p−p∞q∞q∞=12ρ∞v2∞, let for any point in the flow where pressure and velocity are 'p' and 'v', respectively and free-stream pressure and velocity be p∞ and v∞. From Bernoulli's equationp∞+12ρv2∞=p+12ρv2⇒(p−p∞)=12ρ(v2∞−v2)Cp=p−p∞q∞=12ρ(v2∞−v2)12ρv2∞⇒Cp=1−(vv∞)2This equation is valid for incompressible flow only.
Example: Find pressure coefficient at a point on an airfoil where velocity is 220 ft/s, which is in a free stream flow of 100 ft/s.
Solution: pressure coefficient is given as Cp=1−(vv∞)2=1−(220100)2=1−4.84=−3.84Example: Pressure coefficient at a certain point on an airfoil is -4.2.Calculate velocity at this point assuming the flow over the airfoil to be inviscid and incompressible is (a) 50 ft/s and (b) 200 ft/s.
Solution: (a) For inviscid and incompressible flow coefficient of pressure is given as Cp=1−(vv∞)2v=√v2∞(1−Cp)=√(50)2(1−(−3.84))=√2500(1+3.84)=110ft/secalso (b) for v∞ = 200 ft/sec Cp=1−(vv∞)2v=√v2∞(1−Cp)=√(200)2(1−(−3.84))=√40000(1+3.84)=440ft/secExample: The velocity of an aircraft is 100 m/sec. At a given point on the surface of wing flow velocity is 150 m/sec. What is the pressure coefficient at this point?
Solution: Considering the flow to be inviscid and incompressible, Pressure coefficient Cp=1−(vv∞)2=1−(150100)2=−1.25
Solution: Considering the flow to be inviscid and incompressible, Pressure coefficient Cp=1−(vv∞)2=1−(150100)2=−1.25
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